[t.knorrParticipant]

Same has to be done in “render” function

[t.knorrParticipant]

$subtree.slideDown(me.animationShowDuration, me.easing,
    function () {
        var scrolltop = $(b.element).scrollTop();       // <---- EDITED

        var $arrowSpan = $(item.arrow);
            item.isExpanded = true;
            me._arrowStyle($arrowSpan, "", item.isExpanded);
            item.isExpanding = false;
            me._raiseEvent('0', { element: item.element });
            me._calculateWidth();
        }) //animate subtree into view 

        $(b.element).scrollTop(scrolltop);              // <---- EDITED     
//     }, 0);

$subtree.slideUp(me.animationHideDuration, function () {
    var scrolltop = $(b.element).scrollTop();       // <---- EDITED

    item.isCollapsing = false;
    me._calculateWidth();
    var $arrowSpan = $(item.arrow);
    me._arrowStyle($arrowSpan, "", item.isExpanded);
    $subtree.hide();
    me._raiseEvent('1', { element: item.element });

    $(b.element).scrollTop(scrolltop);              // <---- EDITED     
})

[t.knorrParticipant]

Hi Ivo,

So you say its normal, when I just:

this.tableDiv.jqxDataTable("sortBy", this.columns[0].datafield, "asc");
let selection = this.tableDiv.jqxDataTable("getSelection");

this.tableDiv.jqxDataTable("clearSelection");

this.tableDiv.jqxDataTable('selectRow', selection[0].uid);

The selection[0].uid is the old uid (like before the sort)

Then a other (not the selection[0] object) will be selected now!

How can I select the previous selection[0] object

Best Regards,
Thomas

[Author]

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