[NeelamMember]

Hi David,

I had same requirement as you. so used function of jqwidgets to achieve the same. Below is the code to move selected item to another listbox.

var moveSelectedItemsRight = function () {
var items = $(“#listBoxA”).jqxListBox(‘getSelectedItems’);

//var selection = new Array();
var selection = new Array(items.length);
for (var i = 0; i < items.length; i++) {

selection[i] = { label: items[i].label, value: items[i].value };

var str = $("#selectedIds").val(); // get selected ids
var val = items[i].value+',';
if(str.search(val) == -1){
$("#selectedIds").val(str.concat(val));
}

}
$("#listBoxB").jqxListBox({ source: selection, multiple: true, width: 261, height: 228 });
}

$("#singleLeft").bind('click', function () {
moveSelectedItemsRight();
});

[NeelamMember]

Hello,

is anybody there to help me out?

[NeelamMember]

Hi,

As you know, I have to access the value of selected item so its necessary to build the array in your given format. But when my ajax request goes, I am building the array in label, value format to access the value but json dont process it the way it should do.

Shall I need to use json_encode() in php action.

Thanks in advance.

[NeelamMember]

Thanks, worked fine after a lot trail.

[NeelamMember]

Also my client gonna buy Enterprise License + Premium Support + Source Code license. So could you please provide us this feature in that license?

[NeelamMember]

Thanks for reply. but I want this feature as my client is sticked to jqwidget and wants this feature. Please let me know what I can do?

[Author]

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