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jQuery UI Widgets › Forums › Getting Started › jqxtree Cannot set property 'id' of undefined
This topic contains 4 replies, has 2 voices, and was last updated by admin 4 years, 1 month ago.
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Добрый день столкнулся с проблеммой.
хотел в jqxtree отобразить дерево при этом выдает ошибку “Cannot set property ‘id’ of undefined”решил для примера взять пример с сайта
var source = [
{ label: “Item 1”, expanded: true, items: [
{ label: “Item 1.1” },
{ label: “Item 1.2”, selected: true }
]
},
{ label: “Item 2” },
{ label: “Item 3” },
{ label: “Item 4”, items: [
{ label: “Item 4.1” },
{ label: “Item 4.2” }
]
},
{ label: “Item 5” },
{ label: “Item 6” },
{ label: “Item 7” }
];
// Create jqxTree.
$(‘#jqxTree’).jqxTree({ source: source, height: ‘300px’, width: ‘300px’ });ошибка осталась
использую версию
“~/Scripts/jquery-3.5.1.min.js”,
“~/Scripts/jquery – ui – 1.12.1.min.js”jQWidgets_Framework 8.1.4
Good afternoon, I ran into a problem.
I wanted to display a tree in jqxtree and it gives the error “Cannot set property ‘id’ of undefined”decided to take an example from the site as an example
var source = [
{label: “Item 1”, expanded: true, items: [
{label: “Item 1.1”},
{label: “Item 1.2”, selected: true}
]
},
{label: “Item 2”},
{label: “Item 3”},
{label: “Item 4”, items: [
{label: “Item 4.1”},
{label: “Item 4.2”}
]
},
{label: “Item 5”},
{label: “Item 6”},
{label: “Item 7”}
];
// Create jqxTree.
$ (‘# jqxTree’). jqxTree ({source: source, height: ‘300px’, width: ‘300px’});the error remained
I use version
“~ / Scripts / jquery-3.5.1.min.js”,
“~ / Scripts / jquery – ui – 1.12.1.min.js”jQWidgets_Framework 8.1.4
Hi Kyvaldenius,
You may remove jQuery. It is not necessary. The Tree should be created as shown in the samples. I would suggest you download jQWidgets from our website.
Best regards,
Peter StoevjQWidgets Team
https://www.jqwidgets.com/please tell me I understand correctly, you don’t need to install jquery for jqwidgets to work (in the examples, jquery is used everywhere)
Hi Kyvaldenius,
You can try with the examples, too. Remove jQuery and it will still work.
Best regards,
Peter StoevjQWidgets Team
https://www.jqwidgets.com/ -
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