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jQuery UI Widgets Forums Grid Grid addrow function almost works

This topic contains 5 replies, has 2 voices, and was last updated by  Weibing 8 years, 7 months ago.

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  • Grid addrow function almost works #87832

    Weibing
    Participant

    K I’m stumped…
    Here’s my form
    myform = $(‘#newComputer’);

    I grab all the data from my form. I know this works cuz I can alert(rowData) and it looks ok.
    var rowData = JSON.stringify(myform.serializeObject());

    When I try and use rowData in the addrow function all I get is an empty row being added to my grid. However, when I copy the output of alert(rowData) and manually paste into a variable and run the same addrow function below it works perfectly. Is the variable rowData different than the output of alert(rowData)?

    $(“#hardware_grid”).jqxGrid(‘addrow’, null, rowData)

    I hope this makes sense.

    Regards and Thank you.

    Weibing

    Grid addrow function almost works #87860

    Hristo
    Participant

    Hello Weibing,

    You should set Object(or Array) to this row as second parameter to ‘addrow’ method.
    Please, provide us small example if you still have same issue.

    Best Regards,
    Hristo Hristov

    jQWidgets team
    http://www.jqwidgets.com

    Grid addrow function almost works #87872

    Weibing
    Participant

    Thanks Hristo.

    I’m trying to write something that resembles an existing sample, shown below
    // create new row.
    $(“#addrowbutton”).on(‘click’, function () {
    var datarow = generaterow();
    var commit = $(“#jqxgrid”).jqxGrid(‘addrow’, null, datarow);
    });

    Seems straight forward. My version creates the proper key value format,
    var rowData = JSON.stringify(myform.serializeObject());

    Here’s what rowData produces if I console.log or alert() the output.

    {“computerId”:””,”TemplateId”:”68″,”Make”:”Lenovo”,”Model”:”X200″,”Processor”:”Intel Core 2 Duo P8700 (2.53GHz)”,”Memory”:”2048″,”MemConfig”:”1x2GB;1x2GB”,”Drive”:”240GB SSD”,”Rom”:”DVD-ROM/CD-RW Multi”,”Acquired”:”02-01-2010″,”DeviceType”:””,”LSBC”:”qqqqqqqqq”,”Serial”:””,”ProductNumber”:””,”Mac”:””,”AlternateName”:””,”isRetired”:”false”}

    If I just paste this info into a variable it works fine i.e.

    rowData = {“computerId”:””,”TemplateId”:”68″,”Make”:”Lenovo”,”Model”:”X200″,”Processor”:”Intel Core 2 Duo P8700 (2.53GHz)”,”Memory”:”2048″,”MemConfig”:”1x2GB;1x2GB”,”Drive”:”240GB SSD”,”Rom”:”DVD-ROM/CD-RW Multi”,”Acquired”:”02-01-2010″,”DeviceType”:””,”LSBC”:”qqqqqqqqq”,”Serial”:””,”ProductNumber”:””,”Mac”:””,”AlternateName”:””,”isRetired”:”false”}

    But the code below doesn’t work. The grid adds an empty row, like rowData is empty {}. Is there a chance the first line is taking too long to populate rowData and the second line runs with an empty variable? I’m a total noob, so I appreciate the help. Thanks.

    var rowData = JSON.stringify(myform.serializeObject());

    var commit = $(“#hardware_grid”).jqxGrid(‘addrow’, null, rowData)

    Grid addrow function almost works #87873

    Weibing
    Participant

    Here’s my addrow code copied from my source.

    addrow: function (rowid, rowdata, position, commit) {

    var computerData = $(‘#newComputer’).serialize();//grab all form fields

    $.ajax({
    url: ‘getDetails.cfc?method=’addComputer’&’ + computerData,
    type:”POST”,
    async: false,
    success: function(response){
    commit(true);
    alert(rowdata);

    },
    error : function(jqXHR, textStatus, errorThrown){
    alert(errorThrown);
    alert(‘damn’);
    commit(false);
    }
    });

    Grid addrow function almost works #87895

    Hristo
    Participant

    Hello Weibing,

    Try to use this:
    var rowData = myform.serializeObject();
    instead of “var rowData = JSON.stringify(myform.serializeObject());”

    Best Regards,
    Hristo Hristov

    jQWidgets team
    http://www.jqwidgets.com

    Grid addrow function almost works #87901

    Weibing
    Participant

    Yeah..that worked. Thanks for helping out a rookie. You rock.

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