Hi,
I am using addRow method , like
$(“#jqxgrid”).jqxGrid(‘addrow’, null, {“name”:”a” , “contact”:”1234″});
it is adding row with these fields as dataField as well as displayField.
But for column “Name”, want to use “Name” –> “a” as a displayField and its value “1” as a dataField. How to add new row like this?
And one more question, When we export Grid data as a JSON , It is exporting its displayFields, how can we export any particular column’s dataField?
e.g. When we export $(“#jqxgrid”).jqxGrid(‘exportdata’, ‘json’);
The name field should export its value(dataField) “1” instead of (displayField)”a”.
Thanks & Regards,
Snehal.